2=-2t^2+1

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Solution for 2=-2t^2+1 equation: 



2=-2t^2+1

We move all terms to the left:

2-(-2t^2+1)=0

We get rid of parentheses

2t^2-1+2=0

We add all the numbers together, and all the variables

2t^2+1=0

a = 2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·2·1
Δ = -8
Delta is less than zero, so there is no solution for the equation

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